In a circle with centre P, AB is a chord. If the length of a radius is 17 cm and AB = 30 cm, then find the distance of AB from the centre P.
Answer should be 8
Please tell method
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Answer:
Let AB be the chord with length =16cm
OA=radius=17cm
Now, OC⊥AB
Then, AC=CB=8cm (perpendicular drawn from the centre of the circle to the chord,bisects the chord)
∴OC=
(OA
2
−AC
2
)
=
(17
2
−8
2
)
=
(225)
=15cm
Hence, OC=15cm
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