In a circle with centre P. AB is a diameter
and point C is a point other than
A and B. If radius of a circle is 34 cm
and AC = 32 cm. then BC =
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Answer:
Step-by-step explanation:
OX is the perpendicular distance from centre O to the chord AB
∴AX=XB
Now,
AX+XB=AB
⇒2AX=AB
⇒2AX=30
⇒AX=
2
30
⇒AX=15
Again,
AO+OD=AD
⇒2AO=AD
⇒2AO=34
⇒AO=17
△AOX is a right angled triangle
∴AO 2 =OX 2 +AX 2
⇒17 2
=OX 2 +15 2
⇒OX 2 =17 2 −15 2
⇒OX 2 = 64
⇒OX=8cm
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