Math, asked by madpagal6251, 1 year ago

In a circle with centre P, chord AB is drawn of length 13 cm. seg PQ ⊥ chord AB, then find l(QB).

Answers

Answered by abhi178
103
A circle of centre P is drawn , chord AB is drawn of length 13cm as shown in figure. Let Q is the point on AB in such a way that PQ ⊥ AB.

we know, chord is bisected by line passing through centre and perpendicular upon it. here , chord AB is perpendicular upon PQ. so, AQ = QB = AB/2
=> AQ = QB = 13cm/2 = 6.5 cm

hence, length of QB = 6.5 cm
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Answered by mysticd
93
Hi ,

************************************************
We know that ,

The perpendicular from the centre of a

circle to a chord bisects the chord .
******************"******************************

It is given that ,

AB = 13 cm

PQ perpendicular to AB

I( QB ) = AB/2

= 13/2

= 6.5 cm

I hope this helps you.

: )
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Anonymous: Sir i request you to please respond to my messages inbox. Thank you sir !
mysticd: ok
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