in a circle with centre p. chords ab and CD intersect at m at right angle. if angle MAC = 55, then angle MBD = _______
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Answer:
A chord divides the circumference of circle in a way that their mean is circumference of semicircle.
The difference in the length of arcs is inversely proportional to length of chord.
And for mutually perpendicular chords the difference of the length of arcs cut by chords are same
so, CWB−BZD=CXA−DYA
CXA+DZB=AYD+BWC
And they all sum up to give Circumference of circle.
CWB+BZD+CXA+DYA=2πr
CWB+DYA=πr(semicircle).
Step-by-step explanation:
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