Question

in a circle with o centre ab and cd intersect p point angle aoc=100,angle boc=70 then bpc=?​

Answer 1

Answer:

According to question

Given :

∠AOB=100∘ ∠BOC=70∘

∴∠ACD=∠ACP=100∘2∘=50∘

∴ The angle subtended at the centre is twice to that of angle subtended at the circumference by the same arc.

∠BOC=70∘

∴∠BDC=∠BAC=70∘2=35∘

In△APC

∠PAC+∠ACP+∠APC=180∘

∠APC=180∘−50∘−35∘

∠APC=95∘