Question

.In a circle with radius 10 cm. ,two equal chords are at a distance of 8 cm. from the centre. Find the length of chords. *

6 cm. each

11cm .each

12 cm.each

13cm.each
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Answer 1

Answer:

11 cm

Step-by-step explanation:

istance of the chord from the centre = OC = 5 cm (Given)

Radius of the circle = OA = 10 cm (Given)

In ΔOCA:

Using Pythagoras theorem,

OA2 = AC2 + OC2

100 = AC2 + 25

AC2 = 100 – 25 = 75

AC = √75 = 8.66

As, perpendicular from the centre to chord bisects the chord.

Therefore, AC = BC = 8.66 cm

=> AB = AC + BC

= 8.66 + 8.66 = 17.32

AB = 17.32

Answer 2

Answer:

12cm

Step-by-step explanation:

the radius is 10cm te distance is 8cm the lenght of chord is 2,√100-64,2√36,=12