In a circle with radius 10cm, two equal chords are at a distance of 8cm from the centre. Find the length of the chords. *
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Step-by-step explanation:
Distance of the chord from the centre = OC = 5 cm (Given)
Radius of the circle = OA = 10 cm (Given)
In ΔOCA:
Using Pythagoras theorem,
OA2 = AC2 + OC2
100 = AC2 + 25
AC2 = 100 – 25 = 75
AC = √75 = 8.66
As, perpendicular from the centre to chord bisects the chord.
Therefore, AC = BC = 8.66 cm
=> AB = AC + BC
= 8.66 + 8.66 = 17.32
AB = 17.32
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