In a circle with radius 10cm, two equal chords are at a distance of 8cm from the centre. Find the length of the chords
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Answer:
Bhimrao Ramji Ambedkar ([bhɪməɑo ɹæmdʒi ɑmbɛdkɑə][citation needed], 14 April 1891 – 6 December 1956), also known as Babasaheb Ambedkar ([bʌbəsɑheb ɑmbɛdkɑə])[citation needed], was an Indian jurist, economist, politician and social reformer, who inspired the Dalit Buddhist movement and campaigned against social discrimination towards the untouchables (Dalits), while also supporting the rights of women and labour. He was independent India's first Minister of Law and Justice, and considered as the chief architect of the Constitution of India, and a founding father of the Republic of India..
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Step-by-step explanation:
Distance of the chord from the centre = OC = 5 cm (Given)
Radius of the circle = OA = 10 cm (Given)
In ΔOCA:
Using Pythagoras theorem,
OA2 = AC2 + OC2
100 = AC2 + 25
AC2 = 100 – 25 = 75
AC = √75 = 8.66
As, perpendicular from the centre to chord bisects the chord.
Therefore, AC = BC = 8.66 cm
=> AB = AC + BC
= 8.66 + 8.66 = 17.32
AB = 17.32
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