Question

in a circle with radius 13 cm , the length of a chord is 24 cm . then , the distance of the chord from the centre is _ cm ​

Answer 1

Answer:

5 cm

Step-by-step explanation:

Let PQ be a chord of a circle with centre O and radius 13cm such that PQ = 24cm.

From O, draw OM perpendicular PQ and join OP.

As, the perpendicular from the centre of a circle to a chord bisects the chord.

∴ PM = 12cm

In △OMP, we have

OP^2 = OM^2 + PM^2

⇒ 13^2 = OM^2 + 12^2

⇒ OM = 5cm. Hence, the distance of the chord from the centre is 5cm.

Answer 2

Given

• In a circle , there are two chord of length 24 cm each . radius of circle is 13 cm . find the distance of these chords from the centre of the circle

To Find

• Distance of The Chord from Centre

Solution

Given that ,

AB = 24 cm Since OM LAB ⇒OM bisects AB So, AM = 12 cm

⇒ OMA,

⇒ OA² = OM²+ AM²

⇒ OM² - OA²-AM² =

⇒ OM²= 132-122

⇒ OM² = 25

⇒ OM² = 5 cm

Therefore

Hence, the distance of the chord from the centre is 5 cm.

____

Done.