Question

in a circle with radius 13 cm, two equal chords are at a distance of 5 cm from the center. find the length of the chord​

Answer 1

Answer:

(h)2=(p)2+(b)2

(13)2=(5)2+(b)2

169=25+(b)2

169-25=(b)2

144=(b)2

12= b

the length of th chord 12cm+12cm=24cm

Answer 2

Answer:

Now AF = AB [Perpendicular drawn from the centre of the circle to the chord bisects the chord.] ∴ The lengths of the two chords are 24 cm each.

Explanation:

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