In a circle with radius 13 cm, two equal chords are at a distance of 5 cm from the centre.Find the lengths of the chord
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Answer:
Let c is the center of circle.
CA is radius, so CA=13 cm.
AB is the chord, now draw a perpendicular from centre to chord, let it is CN and CN=5cm.
Use pythagoras theorem in triangle ANC,
AN=sqrt(13^2-5^2)
AN=sqrt (144)
AN=12cm.
Chord =2*AN=2*12=24cm
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