Question

In a circle with radius 41cm,
two equal chords are at a
distance of 9cm from the
centre. Find the lengths of the
chord. ​

Answer 1

Answer:

length of chord = 80cm

Step-by-step explanation:

radius of circle = 41cm

distance between the centre and the chord = 9cm

By using Pythagoras theorem, we get

41^2 - 9^2 = base^ 2

1681 - 81 = base^2

1600 = base^2

base = 40cm

therefore length of chord = 2 x 40

= 80 cm