Question

In a circle with radius 5 cm find the lenght of a chord lying at distance 4 cm from the center.

Answer 1

Answer:

6 cm

Step-by-step explanation:

let the center of circle be O

Let the chord be AB

It intersects the chord at point M

OM is perpendicular to AB

therefore,

OM = 4 cm

OB (Radius) = 5 cm

In triangle OMB, By Pythagorus Theorem,

(OB)2 = (OM)2 + (MB)2

(5)2   =  (4)2 + (MB)2

25 = 16 + (MB)2

(MB)2 =  9

MB =  3

AB = 2(MB)

Because,( A perpendicular drawn from the center of the circle to the chord bisects the chord)

Therefore,

AB = 2(3)

AB = 6