Question

In a circle with radius 5cm . The distance of a chord from the center is 3cm. Find the length of the chord.

Answer 1

By Pythagoras theorem,

Radius² = distance² +(half of chord)²

5²=3²+(half of chord)²

25-9=(half of chord)²

16=(half of chord)²

√16 =(half of chord)

4cm =half of chord

2×4 = Lenght of chord


8cm = lenght of chord.



Lenght of chord is 8cm




I hope this will help you



-by ABHAY

Answer 2

Answer:-

Given that :

• Radius of the Circle, (r) = 5 cm

• Distance of the chord from the centre = 3 cm

To find :

• Length of the chord

By phythagoras theorem.

$\huge{\sf{\boxed{\boxed{Solution:}}}}$

[Let AOC is a right angled triangle.]

Therefore,

⇒ AO² + OC² = AC²

⇒ 3² + OC² = 5²

⇒ 9 + OC² = 25

⇒ OC² = 25 - 9

⇒ OC² = 16

⇒ OC = 4

Length of the chord = 4 + 4 = 8 cm.

Hence

$\bold{The\:length\: of \:the \:chord\: is \:8cm}$