Question

in a circle with radius 6 cm a minor arc subtends an angle of measure 60 degree at the center. find the area of the minor sector and the major sector corresponding to their arc​

Answer 1

Given :-

• Radius of circle = 6 cm .
• Angle at centre = 60° .

To Find :-

• Area of minor sector and major sector ?

Solution :-

we know that,

• Area of minor sector = (angle at centre/360°) * π * (radius)² .
• Area of major sector = (360° - angle at centre/360°) * π * (radius)² .

so, putting values we get,

→ Area of minor arc = (60/360) * 3.14 * (6)² = (1/6) * 3.14 * 36 = 3.14 * 6 = 18.84 cm² . (Ans.)

→ Area of minor arc = (360 - 60/360) * 3.14 * (6)² = (300/360) * 3.14 * 36 = (5/6) * 3.14 * 36 = 5 * 3.14 * 6 = 18.84 * 5 = 94.2 cm² . (Ans.)

Answer 2

Answer:

Step-by-step explanation:

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