in a circle with radius r an arc subtends an angle of meausure theta at the center . the area of major sector will be?
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Answer:
area of of circle -area of minor sector
Step-by-step explanation:
pie r square -theta of minor sector .pie r Square
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Radius of circle = r
Angle subtended to form the arc = ∆ [∆ denotes theta here]
Area of minor sector = ∆/360×πr²
Area of circle = πr²
Area of major sector = πr²-∆πr²/360
= (360πr²-∆πr²)/360
= πr²(360-∆)/360
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