In a circuit 3 resistance of equal resistance (A) are connected in parallel. And the current flowing in the circuit is 9/A ampere. Find the voltage applied in the circuit.
Answers
Given :
▪ Three identical resistors of resistance A are connected in parallel.
▪ Current flow in the circuit = 9/A
To Find :
▪ Applied volatge across the parallel connection.
Concept :
↗ This question is completely based on the concept of ohm's law.
↗ As per ohm's law, current flow in the circuit is directly proportional to the applied potential difference. (At constant temperature)
Mathematically,
❇ V = IR
CalculaTion :
➡ Eq. resistance of circuit :
→ 1/Req = 1/R1 + 1/R2 + 1/R3
→ 1/Req = 1/A + 1/A + 1/A
→ 1/Req = 3/A
→ Req = A/3 Ω
➡ Applied potential difference :
→ V = IReq
→ V = (9/A)×(A/3)
→ V = 9/3
→ V = 3 Volt
Answer :
Given that in a circuit 3 resistance of equal resistance (A) are connected in parallel. Current flowing is (9/A) Amphere.
We have to find voltage applied in the circuit.
As we know the formula for finding equivalent resistance in parallel :
→ 1/R (P) = 1/R₁ + 1/R₂ + 1/R₃ + ..........
As the three resistances are equal then , R₁ = R₂ = R₃ = A
Substituting values,
→ 1/R (P) = 1/A + 1/A + 1/A
→ 1/R (P) = (1 + 1 + 1)/A
→ 1/R (P) = 3/A
→ R (P) = A/3 Ω
Νοw we know ohm's law :
→ V = IR
Substituting values,
→ V = 9/A × (A/3)
Cancelling out A from both :
→ V = 9/3
→ V = 3 volts.
∴ Voltage applied in curcuit = 3 volts. ✓