In a circuit 60v battery three resistance s r1= 10 ohms r2=20 ohms and r3= x ohms are connected in series if 1 ampere current flows in the circuit find the resistance inr3 by using Kirchhoff' s loop law
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Since it is in series...
sum of resistance= total resistance= 10+20+X
V= I×R
using the formula...
60/(10+20+X) = 1
==> X=30 ohms
I hope it helps
please follow for more explanations...
sum of resistance= total resistance= 10+20+X
V= I×R
using the formula...
60/(10+20+X) = 1
==> X=30 ohms
I hope it helps
please follow for more explanations...
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