In a circuit a 33 ohm resister carries a curren of 2 A. The voltage accross the resistor is
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V=IR
V=2×33
V=66v
is the answer
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Here is ur answer
By ohm's law
V = IR
here, R = 33 ohm
I = 2A
So, V = 33 x 2 = 66V
Hope it helps uh
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