In a circuit, a resistor of resistance 10Ω is connected across a battery of 12 Volts. Calculate the current in the circuit. Now an ammeter of resistance 0.2Ω is connected in the circuit, calculate the ammeter reading.
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First of all, thos question is from physics.
Case-I
V=12V,
R=10ohm
V=IR
12=Ix10
I=1.2A
Case-II
V=12V
R=10ohm +0.2ohm
=10.2ohm
V=IR
6=Ix10.2
I=1.568A
Case-I
V=12V,
R=10ohm
V=IR
12=Ix10
I=1.2A
Case-II
V=12V
R=10ohm +0.2ohm
=10.2ohm
V=IR
6=Ix10.2
I=1.568A
Avitesh1:
Sorry for that
No problem mate, just be careful next time because we scroll down in the subjects which we think we are good at.
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