In a circuit below calculate (1) calculate total effective resistance (2) the total current through the circuit (3) potential different across 4 ohm and 2 ohm
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1) total resistance:-
4 ohm and 2 ohm are in series combination
so, R = 4+2
R = 6 ohms
Let this resistance be r¹
now, r¹ and 6 ohms are in parallel combination
so, 1/R = 1/6 + 1/6
1/R = 2/6
1/R = 1/3
R = 3 ohms
Let this resistance be r²
Total resistance = r¹ + r²
= 6+3
= 9 ohms
2) total current:-
current = potential difference/resistance
current = 6V/9ohms
= 0.6 ampere
3) potential difference:-
potential difference = current × resistance [ by ohm's law]
current for 4 ohm and 2 ohm = 1 ampere
because, 6 volts ÷ 6 ohms = 1 amp.
v = 1 ampere × 6 ohms
v = 6 volts
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