In a circuit capicotor has potential difference ∆V charge Q and Capicitance C. If potential difference is double the Capicitance will be,.?
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We have capacitance , C=Q/V ,
where Q= charge on capacitor ,
V= potential difference across the plates ,
when the potential difference V is increased , charge on capacitors also increases such that the ratio Q/V , remains constant i.e. capacitance remains constant . Because capacitance depends upon plate area , medium between plates and distance between plates .Therefore when potential difference is increased to 2V , capacitance will be C.
Explanation:
this is correct answer and but you can confirm to your teacher
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