Physics, asked by farihakhalid4748, 4 months ago

In a circuit capicotor has potential difference ∆V charge Q and Capicitance C. If potential difference is double the Capicitance will be,.?​

Answers

Answered by paragtiwari
0

Answer:

We have capacitance , C=Q/V ,

where Q= charge on capacitor ,

V= potential difference across the plates ,

when the potential difference V is increased , charge on capacitors also increases such that the ratio Q/V , remains constant i.e. capacitance remains constant . Because capacitance depends upon plate area , medium between plates and distance between plates .Therefore when potential difference is increased to 2V , capacitance will be C.

Explanation:

this is correct answer and but you can confirm to your teacher

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