in a circuit one resistance of 10ohm is in series and two resistances of 20ohm and 30ohm are in parallel there are 3 ammetrs after each resistance . if ammeter of 20ohm resistance shows a reading of 2.4A find the readings of other two resistances
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Resistance Ω is in series with the parallel combination of 20Ω and 30Ω. Current in 20 Ω is 2.4 A.
Voltage across 20Ω: 20×2.4= 48V.
So the Current across 30Ω: 48/30 = 1.6 A.
Current in Ω: sum= 2.4+1.6 = 4.0 A.
Voltage across 20Ω: 20×2.4= 48V.
So the Current across 30Ω: 48/30 = 1.6 A.
Current in Ω: sum= 2.4+1.6 = 4.0 A.
kvnmurty:
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