Question

in a circuit, potential difference of battery is 6volts .There are 3 resistors each of resistance 3ohm, 2ohm, 1ohm. find the current flowing through 1ohm resistor.(they are in series Connection) ​

Answer 1

Answer:

Answer is 1 ampere

Explanation:

Series connection

R = R1 + R2 + R3

R = 3 + 2+ 1

R = 6 Ohm

I = V/R

I = 6 / 6

I = 1 ampere

Answer 2

Given that, three resistors of resistance 3ohm, 2ohm and 1 ohm are connected in series across a 6V battery.

We have to find the current flowing through 1ohm resistor.

Let's denote the first resistor i.e. 3ohm by R1, 2ohm by R2 and 1ohm by R3.

R1, R2 and R3 are connected in series and the potential difference is 6V as shown below:

-------| R1 |------| R2 |-------| R3 |-------

----------------------| V |-----------------------

For series combination:

Rs = R1 + R2 + R3

For parallel combination:

1/Rp = 1/R1 + 1/R2 + 1/R3

Given in question that, all the resistors are connected in series. So,

Rs = R1 + R2 + R3

Substitute value of R1 = 3ohm, R2 = 2ohm and R3 = 1ohm

Rs = 3 + 2 + 1

Rs = 3 + 3

Rs = 6

Therefore, the equivalent resistance of all the three resistors in series is 6ohm.

From ohm's law we can say that,

V = IR

From above calculations we have R = 6ohm and V = 6V (given in question)

Substitute the value of R and V to find the value of I (current).

6 = I × 6

6/6 = I

1 = I

(All the resistors are connected in series and in series current is same.)

Therefore, the current flowing through 1ohm resistor is 1A.