Question

IN a circuit shown in the figure given alongside , calculate the current flowing through the arms AB,AC and CDE the potential difference across AB,CD and DE.



Note = Spam answer will deleted

Answer 1

The voltage across the arms are same = 1.5 V

Current in arm AB

= $\bf\huge\frac{V}{R}$

= $\bf\huge\frac{1.5V}{12}$

= 0.125A

Current in the arm CDE

= $\bf\huge\frac{V}{R}$

= $\bf\huge\frac{1.5V}{6 + 4}$

= $\bf\huge\frac{1.5V}{10}$

= 0.15A

Current in arm AC ⇒ CDE = 0.15A

Potential Difference AB = 1.5V

Potential Difference CD = Current × Resistance

= 0.15 × 6

= 0.9V

Potential Difference DE = Current × Resistance

= 0.15A × 4

= 0.6V

Answer 2

Answer:

plz mark me as brainlist