Question

In a circuit, the potential difference across resistance is V = (8 0.5) V and the current through resistance I = (2+0.2) A. The percentage error in the measurement of resistance is (a) 6% (b) 12% (c) 14.5% (d) 16.25% The nressure P is given bat2 TI 19​

Answer 1

Answer:

nahi pata bhai sorry maaf karde

Answer 2

$\huge❥\huge{\underline{\mathtt{\red{A}\pink{n}\green{s}\blue{w}\purple{e}\orange{r}\green}}}࿐$

(2 + 11.25%)

Resistance, 

$\huge\frac{r}{1}$

      

V=(8 + 0.5)V

 L=(4 + 0.2)A

R=IV=48=2Ω

We know from rules of error propagation.

$\large\frac{ΔR=ΔV+ΔI}{r \: \: \: \: \: \: \: \: v \: \: \: \: \: \: \: i}$

       

$\huge\frac{0.5 \: \: + \: \: 0.2}{8 \: \: + \: \: 4}$

∴  % error =11.25%

⇒  R=(2±11.25)%