Question

In a circuit three resistances of 10 Ω, 20 Ω & 60 Ω are connected in parallel to a battery of 24 V. Calculate the total current in the circuit.

(1 Point)

(a) 6 A

(b) 8 A

(c) 10 A

(d) 4 A​

Answer 1

Answer:

d) 24

Explanation:

1/10+1/20+1/60=6+3+1/60 (coz in parallel)

V=24

so,24/1/6=24/6=4A

Answer 2

Answer:

Current through 1st resistor = V/R1 = 24/10

Current through 2nd resistor = V/R2 = 24/20

Current through 3rd resistor = V/R3 = 24/60

Total current = I 1 + I 2 + I 3

= 2.4 + 1.2 + 0.4 = 4A

Your answer is 4A. As the resistances are connected in parallel the value of voltage does not change so I found current through each resistor and added them.

Hope this helps you! If so please mark my answer as brainliest dude