Question

In a circuit three resistor connected in a series , they are 5 ohm , 9ohm & 11ohm and also two resistor connect in parallel , they are 10 ohm & 4 ohm then what will be total resistance of this circuit .?​

Answer 1

Solution

Given :-

• Three resistor connected in series , 5 ohm , 9ohm & 11ohm
• Two are connected in parallel , 10 ohm & 4 ohm

Find :-

• total resistance of circuit

Explanation

Using Formula

For Series Connection

★ R = r + r' + r"

For Parallel connection

★ 1/R' = 1/r + 1/r'

Where,

• R , R' are total resistance in series & parallel connection
• r , r' & r" are resistor

Here,For Series Connection

• r = 5 ohm
• r' = 9 ohm
• r" = 11 ohm

Then, total resistance

==> R = 5 + 9 + 11

==> R = 25 ohm

Now for parallel connection

Total resistance

==> 1/R' = 1/10 + 1/4

==> 1/R' = ( 2 + 5)/20

==> 1/R' = 7/20

or,

==> R' = 20/7 ohm

So , Now

If we find total resistance of whole connection then both both resistance will be in series connection.

So,

==> R" = R + R'

==> R" = 25 + 20/7

==> R" = (25×7 + 20)/7

==> R " = (175 + 20)/7

==> R" = 195/7 ohm

Hence

• Total resistance of whole connection will be = 195/7 ohm

__________________

Answer 2

Hey there!

•Total resistance of the whole connection is 195/7 ohm.

•Please refer to the solution being attached for step by step explanation!

• Hope it helps.