in a circular path outer circumference exceeds the inner circumference by 132m and the area of the path is 9702 sq.m. Find the area of the field inside the path.
Answers
Answered by
3
Answer:
Correct option is
C
21m
Given, 2πr
2
−2πr
1
=132
⇒r
2
−r
1
=
2π
132
=
44
132×7
m=21m
i.e., width of the path =21m
Step-by-step explanation:
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