Question

in a circular table cover of radius 32cm a design is formed leaving an equilateral triangle ABC in the middle show in figure find the area of design​

Answer 1

Answer:

this is the answer

hope you understand it

Answer 2

Step-by-step explanation:

if we consider the height of the trangle is made of radius which is 2/3 rd part of height and the remaining is 1/3 rd part.

1/3 part=32/2=16cm.

so height of triangle=32+16=48 cm

so a rt angled trianhle is formed which consist of hypotenuse h, sideh/2 and side48 cm

by pythagoras theorem

h square=(h/2)square+48 square

3/4 h square=2304

h=55.42cm

from here we can find h.

area of triangle=root3/4×side square=1330cm square

area of circle=pi×r square=3215.36cm square

area of design=area of circle-area of triangle=3215.36-1330 =1885.36cm square