In a circular track (distance 400 m) an athlete runs 1/4 the of the ground. So what would be the displacement?
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Explanation: 90.02 m
could you please give step by step explanation...plz
In case of a circular motion along a track 400 m long, if a body moves for 1/4th of the total distance of the track.
Then, the displacement is given by AB, let us find the distance A toB. C = 2 π r
r = 400 / 2π
r = 63.66 m
In triangle AOB,
AB² = AO² + OB ² (AO = OB ... radii of the same circle)
AB² = 8105.19
AB = 90.02 m
Then, the displacement is given by AB, let us find the distance A toB. C = 2 π r
r = 400 / 2π
r = 63.66 m
In triangle AOB,
AB² = AO² + OB ² (AO = OB ... radii of the same circle)
AB² = 8105.19
AB = 90.02 m
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