Question

In a city 70% travel by bus and 50% travel by car find percentage travelling by both bus and car

Answer 1

Answer:

P(C) = Probability that a person travels by car = (70 / 100) = 0.7

P(B) = Probability that a person travels by bus = (50 / 100) = 0.5

Now, as per condition,

P(C union B) = Probability that a person travels either by car or by bus = 1.

Thus, P(C union B) = P(C) + P(B) - P(C intersect B)

So, P(C intersect B) = 0.2.

So, the percentage of people who travel both by car and by bus = 0.2 * 100% = 20%.

Answer 2

Answer:

120%

Step-by-step explanation:

People travel by bus = 70%

People travel by car = 50%

Solution :

70% + 50% = 120%

Thus,120% people travelled by bus and car .

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