In a city, a person own independently a sedan car with probability 3/10 and SUV with probability 410.410. If he has sedan only, then he keeps a driver with probability 6/10, whereas if he owns SUV only, then he keeps a driver with probability 7/10, whereas if he keeps both type of cars then his probability of keeping a driver is 9/10. Then
Answers
Given: a person own independently a sedan car with probability 3/10 and SUV with probability 4/10.
If he has sedan only, then he keeps a driver with probability 6/10
If he has SUV only, then he keeps a driver with probability 7/10
if he keeps both type of cars then his probability of keeping a driver is 9/10.
To Find :
Probability of keeping driver
Probability that he owns SUV if he keeps a driver
Solution:
Probability Sedan car = P(A) = 3/10
Proabability SUV car = P(B) = 4/10
A and B are independent events
Hence P (A ∩ B) = P(A).P(B) = (3/10)(4/10) = 12/100
Proabability Sedan only = P(A) -P (A ∩ B) = 3/10 - 12/100 = 18/100
Proabability SUV only = P(B) -P (A ∩ B) =4/10 - 12/100 = 28/100
Probability both = 12/100
probability of keeping a driver= (18/100)(6/10) + (28/100)(7/10) + (12/100)(9/10)
= (108 + 196 + 108)/1000
= 412 /1000
Probability that person keeps driver = 412/1000
probability own SUV if he keeps driver = ( 196 + 108 ) / 412
= 304/412
= 76/103
Probability that he owns SUV if he keeps a driver = 76/103
Learn More:
7cm long stick cut in three pieces. Length of each piece is natural number.
What is the probability of forming triangl...
brainly.in/question/37342919
Ang, Ben, and Jasmin each have 5 blocks, colored red, blue, yellow, white, and green; and there are 5 empty boxes. Each ...
brainly.in/question/34973202
If a die is rolled twice, what is the probability that the sum of the points is more than 9
brainly.in/question/8806537