Question

In a city ABC, the population of males decreased by 8% from 2018 to 2019. If the male population in 2018 was 7200, then find the male population in 2019.​

Answer 1

Answer:

7200*8/100=576

7200-576=6624

Explanation:

Answer 2

Given:

In a city, ABC, the population of males decreased by 8% from 2018 to 2019. If the male population in 2018 was 7200

To find:

The male population in 2019.​

Solution:

To solve the given problem we will use the following formula:

$\boxed{\bold{A = P [1 - \frac{R}{100} ]^n}}$

where A = population after n years, P = initial population, R = rate of decrease and n = no. of years

The rate of decrease of population of males, R = 8%

The no. of years, n = 2019 - 2018 = 1 year

The initial population of males in 2018 was, P = 7200

Now, by substituting the given values of P, R and n in the above formula, we get

$A = 7200 [1 - \frac{8}{100} ]^1}}$

$\implies A = 7200\times [\frac{100 - 8}{100} ]$

$\implies A = 7200\times [\frac{92}{100} ]$

$\implies A = 72 \times 92$

$\implies \bold{A = 6624}$ ← population in 2019

Thus, the male population in 2019 is → 6624.

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