In a city B, for a journey of 8km, the charge paid is Rs91 and for a journey of 14km, the charge paid is Rs 145.The graph of lines representing the conditions are: (situation 2)Immersive Reader
(1 Point)
PARALLEL LINES
INTERSECTING LINES
PERPENDICULAR LINES
COINCIDENT LINES
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Let the fixed charges of taxi be Rs x and the running charges be Rs y km/hr.
According to the given condition, we have 0
x+10y=75 .(i)
x+15y=110 .(ii)
Subtracting equation (ii) from equation (i), we get
−5y=−35⇒y=7
Putting y=7 in equation (i), we get x=5
∴ Total charges from travelling a distance of 25km
=x+25y
=Rs.(5+25×7)=Rs.180.
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