Math, asked by karishma5277, 1 month ago

In a city B, for a journey of 8km, the charge paid is Rs91 and for a journey of 14km, the charge paid is Rs 145.The graph of lines representing the conditions are: (situation 2)Immersive Reader
(1 Point)
PARALLEL LINES
INTERSECTING LINES
PERPENDICULAR LINES
COINCIDENT LINES

Answers

Answered by navprabjot
2

Answer:

Let the fixed charges of taxi be Rs x and the running charges be Rs y km/hr.

According to the given condition, we have 0

x+10y=75 .(i)

x+15y=110 .(ii)

Subtracting equation (ii) from equation (i), we get

−5y=−35⇒y=7

Putting y=7 in equation (i), we get x=5

∴ Total charges from travelling a distance of 25km

=x+25y

=Rs.(5+25×7)=Rs.180.

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