Question

In a city_it_was found that the amount of daily deposit of pollutant is
3.2 x 10-5 g/cm². If the city has an area of 400 square kilometre and the pollutant
6.
-
is distributed evenly, find the amount of pollutant that falls on the city."
(i) in one day
(ii) in one year
10. For

Answer 1

Answer:

The amount of pollutant that falls on the city in a year = 1.28*105*365=467.2*105=4.672*107 kg

Step-by-step explanation:

the amount of daily deposit of pollutant = 3.2*10−5 g/sq cm=3.2*10−5*104=3.2*10−1 g/sq m3.2*10-5 g/sq cm=3.2*10-5*104=3.2*10-1 g/sq m

the area of the city = 400 sq km =400*103*103 =400*106 sq m=400*103*103 =400*106 sq m

therefore the amount of pollutant that falls on the city in a day 3.2*10−1*400*106=1280*105=1.28*108 gm=1.28*105 kg3.2*10-1*400*106=1280*105=1.28*108 gm=1.28*105 kg

the amount of pollutant that falls on the city in a year = 1.28*105*365=467.2*105=4.672*107 kg