Question

- In a city no two persons have identical set of teeth and there
is no person without a tooth. Also no person has more than
32 teeth. If we disregard the shape and size of tooth and
consider only the positioning of the teeth, the maximum
population of the city is
(plz answer with explaination)​

Answer 1

Answer:

$2^{32} -1$

Step-by-step explanation:

A human being has 32 places for teeth.

Each spot can either have a tooth or there is no tooth

∴ There are two options for each place

As there are 32 such places, $2^{32}$ such combinations are possible.

Since there is no person without a tooth, Maxiumum possible population becomes $2^{32} - 2^{0}$ = $2^{32} -1$

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