In a city the population of female increase from 100000 to 133100 in three years find the annual rate of growth
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The present population of a city is 3,02,500. If the population increases by 10% every year, what was the population of the city two years ago?
A
2,80,000
B
2,75,000
C
2,48,000
D
2,50,000
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ANSWER
Let the population before two years ago be x
Given the population increases by 10%
So increase in population after one year is 10010×x=0.1x
So population after one year is x+0.1x=1.1x
Increase in population after another one year is 10010×1.1x=0.11x
So population at present is 1.1x+0.11x=1.21x
But given population at present is 3,02,500
⟹1.21x=302500
⟹x=1.21302500=2,50,000
Population of city two years ago is 2,50,000
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