Question

in a city total number of people was 8000. in one year male increase 10% and female increase 8% but total number of people increased 9%. total number of male in the city.​

Answer 1

Answer:

Step-by-step explanation:

let males be x ,females be y

we know that x+y =8000(knowing there are no transgenders) .......(1)

increase in males is 10%

there fore new number of males is 110x/100

=1.1x

increase in females is 8%

therefore new number of femalse is 1.08y

new population=1.1x +1.08 y

also that it is given that there is increase by 9% in entire population

so new population = 8720 people=1.1+ 1.08y ................(2)

solving 1 and 2

female population y = 4000

x=4000

initial number of males is 4000

and final number of males is 4400

please mark me the brainliest

Answer 2

hi buddy

here is your answer

$9percentage \: = 8000 \times 9 \div 100$

$= 720$

$now \: let \: men \: were \: \: x$

$therefore \: women \: were8000 - x$

$now \: increased \: in \: men \: are \: 10percentage$

$\frac{10 x}{100}$

$\frac{x}{10}$

$= \frac{8}{100} (8000 - x)$

$= \frac{64000}{100} - \frac{8x}{100}$

$640 - \frac{2x}{25}$

$25x - \frac{20x}{250} = 80$

$5x = 80 \times 250$

$x = 80 \times \frac{250}{5}$

$x = 4000$

=400

=320

hope it helps you

#Sibi ❤