Question

In a class, 1/5 of it secured first division, 1/10
of it secured second division and the
remaining 70 students secured third division.
Assuming that no student of the class had
failed, find the total number of students in the
class.Take the total number of students to be x.​

Answer 1

Answer:

100.

Step-by-step explanation:

Here, the total number of students are x.

According to the situation :

1 / 5 of total students scored 1st division, it means 1 / 5 of x scored 1st division.

1 / 10 of total students scored 2nd division, it means 1 / 10 of x scored 2nd division.

Remaining students are 70.

Here,

= > students who scored 1st division + students who students 2nd + 70 = total students

= > ( 1 / 5 of x ) + ( 1 / 10 of x ) + 70 = x

= > x / 5 + x / 10 + 70 = x

= > 70 = x - x / 5 - x / 10

= > 70 = x( 1 - 1 / 5 - 1 / 10 )

= > 70 = x( 10 - 2 - 1 ) / 10

= > 70 = x( 7 / 10 )

= > ( 70 × 10 ) / 7 = x

= > 100 = x

Hence the total students in the class are 100.

Answer 2

students with first division = 1/5 of x students with second division= 1/10 of x students with third division= 70 (given){no one failed}

rest is in the attachment and I forgot to put the signs on the left side