Question

in a class, 30% of the students offered English, 2096 offered
Hindi and 10% offered both. If a student is selected at random
what is the probability that he has offered English or Hindi?​

Answer 1

Answer:

p(class)=10/100

=1/10

p(hindi)=20/100

=1/5

p(english)=30/100

=3/10

=p(e)+p(h)-p(c)

={3/10+1/5-1/10}

=4/10

=2/5 answer