Question

In a class, 40 % of students are boys. 60 % of girls are rank holders. 40 % of students are rank holders. Find the number of boys with rank, if class strength is 50 ?

Answer 1

Answer: 8

                                                =40*50/100=20

                                                  =40*20/100

                                                   =8

Answer 2

Answer:

Step-by-step explanation:

Percentage:

• In mathematics, a ratio or number that can be written as a fraction of 100 is referred to as a percentage.
• To determine q as a percentage of a $=\frac{q}{100} *a$
• $80$ percentage of $50$ is $= \frac{80}{100} * 50 =8*5=40$

Given:

• Class strength $=50$
• $40$ % of students are boys.
• $60$ % of girls are rank holders.
• $40$ % of students are rank holders.

To Find:

We need to find the number of boys with rank.

Solution:

Lets convert percentage into number of students.

Number of boys in class is $40$ % of $50$.

⇒  $\frac{40}{100} *50$

⇒  $4*5$

⇒  $20$

∴ $20$ students are boys.

Number of girls in class.

⇒  $50-20$

⇒  $30$

∴ $30$ students are girls.

Number of girls with rank is $60$% of $30$.

⇒  $\frac{60}{100} *30$

⇒  $6*3$

⇒  $18$

∴ Number of girls with rank is $18$.

Number of rank holders in the class is  $40$ % of $50$.

⇒  $\frac{40}{100} *50$

⇒  $4*5$

⇒  $20$

∴ $20$ students are rank holders.

Number of boys with rank is to subtract the number of girls with rank from total number of rank holders.

⇒ $20-18$

⇒  $2$

Therefore, number of boys with rank is $2$.

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