Question

in a class 60 where girls are twice that of boy Sanjay ranked 17th from the top if there are boys ahead of Sanjay how many boys are after him in the rank​

Answer 1

Answer:

You have not mentioned the number of boys ahead of Sanjay, so let it be 7.

Let the no of boys in the class be x

therefore the no of girls in the class=2x

the total no of students in the class =60

2x + x =60

3x=60

x=20

therefore the no of girls and boys on the class is 40 and 20 respectively.

there are 9 boys ahead of Sanjay, therefore no of boys behind him= total no of boys-10(since Sanjay is also a boy)

=20-10

=10.

THEREFORE THERE ARE 10 BOYS AFTER SANJAY IN THE RANK.