Math, asked by shreya6998, 1 year ago

In a class 8 student out of 28 have a dog as their pet animal at home 6 student have a cat as their pet animal 10 student have daog and cat both then how many students do Not have a dog or cat as their pet animal at home

Answers

Answered by chandan727299
7
4 students have not have a dog or cat

because
28-8=20
20-6=14
14-10=4

I hope it helps u

shreya6998: Thank you so much for the help
chandan727299: you are most welcome
Answered by meenag9065
2

Step-by-step explanation:

i. Let U be the set of student , D be the set of students who have dog and C be the set of students who have cat.

n(U) = 28, n(D) = 8, n(C) = 6,

Number of students who drink Tea and Coffee = n(D ∩ C) = 10

ii. n(D ∪ C) = n(D) + n(C) – n(D ∩ C)

n(D U C) = 8 + 6 – 10

∴ n(D ∪ C) = 4

4 students do not have a dog or cat as their pet animal at home.

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