Math, asked by AdityaMadankar, 1 year ago

In a class, 8 students out of 28 have only dog as their pet animal at home, 6 students have
only cat as their pet animal. 10 students have dog and cat both, then how many students
do not have a dog or cat as their pet animal at home?


AdityaMadankar: please can anyone answer

Answers

Answered by Bhavyanayak
37

Totally 28 students are there.

8 students have dog as their pet animals.

6 students have cat as their pet animals.

10 students have cat and dog both.

So the remaining students :

28 - (+8 + 6 + 10)

28 - 24

4 students.

Hence, the remaining 4 students do not have a dog or a cat as their pet animal at home.


Bhavyanayak: Is it correct?
AdityaMadankar: yes
Bhavyanayak: That was simple.. :-)
AdityaMadankar: I was confused in putting values
Bhavyanayak: Oh..
Answered by meenag9065
6

Step-by-step explanation:

i. Let U be the set of student , D be the set of students who have dog and C be the set of students who have cat.

n(U) = 28, n(D) = 8, n(C) = 6,

Number of students who drink Tea and Coffee = n(D ∩ C) = 10

ii. n(D ∪ C) = n(D) + n(C) – n(D ∩ C)

n(D U C) = 8 + 6 – 10

∴ n(D ∪ C) = 4

4 students do not have a dog or cat as their pet animal at home.

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