In a class, 80% of the students play cricket, 85% play football and 75% play both cricket and football. If 40 students
do not play either cricket or football, find the total number of students.
Answers
Step-by-step explanation:
So 80 of them play either football or cricket, and 0.35 x 80 = 28 students play only cricket. So 80 - 28 = 52 students play football (note: any of these 52 students can play only football or both football and cricket). Therefore, the percent of students who play football is 52/100 = 52%.
Concept:
Set theory is the branch of mathematical logic that studies sets.
Given:
We are given that:
80% of the students play cricket
85% play football
75% play both cricket and football
40 students do not play either cricket or football.
Find:
We need to find the total number of students.
Solution:
P(C) = 80% = 0.8
P(F) = 85% = 0.85
P( C ∩ F) = 75% = 0.75
P( C ∪ F ) = P(C) +P(F) - P(C ∩ F)
P( C ∪ F ) = 0.8 + 0.85 - 0.75 = 0.9
P'( C ∪ F ) = 1 - P( C ∪ F ) =1 - 0.9 = 0.1
Let the total number of students be x
ATQ:
0.1 x = 40
x = 400.
Therefore, we get that the total number of students are 400.
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