Question

In a class if 25 children 8 out of the 10 boys and 6 of the 15 girls are in the atletics team.A child from the class i9s chosen to lead the team on the sports day.Find the probability that the child chosen is

(1) in the athlete team

(2) female

(3) a female member of the atlete team​

Answer 1

Given,

Total number of children's = Total number of outcomes = 25  

Probability of an event =

possible number of outcomes / total number of outcomes

As per the question,

1) P(child chosen is in the athlete team)

= (boys present in athlete team + girls present in athlete team) / total number of children's

= $\frac{14}{25}$

= $0.56$

2) P (child chosen is a female)  

= total number of girls / total number of students  

= $\frac{15}{25}$

= $0.60$

3) P(child chosen is female member of athlete team)

= girls present in athlete team / total number of students  

= $\frac{6}{25}$

= $0.24$

Answer 2

Answer:

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