Question

In a class of 100, 35 like science and 45 like math. 10 like both. How many like either of them and how many like neither?

Answer 1

Given:

Total number of students that are there in the class n(T)

= 100 students

Number of students who like science subject n(S)

= 35 students

Number of students who like math subject n(M)

= 45 students

Number of students who like both the subjects n(M ∩ S)

= 10 students

Calculating the number of students who like either of them:

n(MᴜS) = n(M) + n(S) – n(M∩S)

Substituting the values known to us in this formula we get:

= 45+35-10

= 70

Therefore, 70 students either like maths or science subjects.

Calculating the number of students who neither like maths or science:

n(T) – n(MᴜS)

Substituting the values known to us in this formula we get:

= 100 – 70

= 30

Therefore, 30 students neither like math or science subjects.

Answer 2

THIS IS THE ANSWER.... PLEASE MARK AS BRAINLEIST!

THANKS