In a class of 100 students,60play cricket ,50 play a volley ball and 28 play both.find the number of students who play atleast one of the two games.
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Total no. of students = 100
No. of students playing cricket = 60
No. of students playing volleyball = 50
No. of students playing both = 28
So, No. of students playing only cricket = 60 - 28 = 32
So, No. of students playing only volleyball = 50 - 28 = 22
Therefore, students playing one game = 32 + 22 = 54
Therefore, students playing atleast one game = 54 + 28 = 82
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No. of students playing cricket = 60
No. of students playing volleyball = 50
No. of students playing both = 28
So, No. of students playing only cricket = 60 - 28 = 32
So, No. of students playing only volleyball = 50 - 28 = 22
Therefore, students playing one game = 32 + 22 = 54
Therefore, students playing atleast one game = 54 + 28 = 82
Plz mark as Brainliest if I helped U....
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Let C=students who play cricket
V=students who play volley ball
n(C∪V)=n(C)+n(V)-n(C∩V)= 60+50-28=110-28=82
V=students who play volley ball
n(C∪V)=n(C)+n(V)-n(C∩V)= 60+50-28=110-28=82
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