Math, asked by nakshalathy, 1 year ago

In a class of 100 students,60play cricket ,50 play a volley ball and 28 play both.find the number of students who play atleast one of the two games.

Answers

Answered by GovindKrishnan
8
Total no. of students = 100
No. of students playing cricket  = 60
No. of students playing volleyball = 50
No. of students playing both = 28

So, No. of students playing only cricket = 60 - 28 = 32
So, No. of students playing only volleyball = 50 - 28 = 22
Therefore, students playing one game = 32 + 22 = 54

Therefore, students playing atleast one game = 54 + 28 = 82

Plz mark as Brainliest if I helped U....
Answered by rdahin
2
Let C=students who play cricket
V=students who play volley ball

n(C∪V)=n(C)+n(V)-n(C∩V)= 60+50-28=110-28=82
Similar questions