In a class of 140 students, 60 play football, 48 play hockey and 75 play cricket, 30 play hockey and cricket, 18 play football and cricket, 42 play football and hockey and 8 play all the three games. Use Venn diagram to find
i. students who do not play any of these three games.
ii. students who play only cricket.
iii. students who play football and hockey, but not cricket.
prmkulk1978:
I think , the question has some wrong data. But i have answered it according to given data.
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Answered by
38
Answer:
Step-by-step explanation:
This data is wrong as Only Hockey can not be 48
Only H = H - H∩C - F∩H + (F∩H∩C)
=> only H = 48 - 30 - 42 + 8 = -16
Which is not possible Let say 48 is 84
Total Students = F + H + C - H∩C - F∩C - F∩H + (F∩H∩C) + (F'∩H'∩C')
=> 140 = 60 + 84 + 75 - 30 - 18 - 42 + 8 + (F'∩H'∩C')
=> 140 = 137 + (F'∩H'∩C')
=> (F'∩H'∩C') = 3
students who do not play any of these three games. = 39
only C = C - H∩C - F∩C + (F∩H∩C)
=> only C = 75 - 30 - 18 + 8
=> only C = 35
Students who play football and hockey, but not cricket = F∩H - (F∩H∩C) = 42 - 8 = 34
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Answered by
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Step-by-step explanation:
see the give attached picture
hope u understand....
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